Use the general power rule twice to differentiate.
f(x)=(9x−5−6)+x6\displaystyle {f{{\left({x}\right)}}}={\sqrt[{{6}}]{{{\left({9}{x}^{{-{{5}}}}-{6}\right)}+{x}}}}f(x)=6(9x−5−6)+x
f′(x)=\displaystyle {f}'{\left({x}\right)}=f′(x)=
Preview Question 6
Submit Try a similar question