Differentiate
f
(
x
)
=
2
csc
−
1
(
2
x
)
\displaystyle {f{{\left({x}\right)}}}={2}{{\csc}^{{-{1}}}{\left({2}{x}\right)}}
f
(
x
)
=
2
csc
−
1
(
2
x
)
. Use exact values.
f
′
(
x
)
=
\displaystyle {f}'{\left({x}\right)}=
f
′
(
x
)
=
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