If $\displaystyle {f{{\left(-{4}\right)}}}={5}$, and $\displaystyle {f}'{\left(-{4}\right)}=-\frac{{1}}{{2}}$.
Let $\displaystyle {{f}^{{-{1}}}{\left({x}\right)}}$ be the inverse function of $\displaystyle {f{{\left({x}\right)}}}$.

$\displaystyle {\left({f}^{{-{{1}}}}\right)}'{\left({5}\right)}=$Preview Question 6 Part 1 of 2  

Write the equation of the tangent line to $\displaystyle {{f}^{{-{{1}}}}{\left({x}\right)}}$ at $\displaystyle {x}={5}$.
$\displaystyle {y}=$Preview Question 6 Part 2 of 2