Solve the initial-value problem for y\displaystyle {y} as a function of x\displaystyle {x}. (4x2)dydx=1,y(0)=4\displaystyle {\left({4}-{x}^{{2}}\right)}\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}={1},{y}{\left({0}\right)}={4}

y=\displaystyle {y}=