Let y=1.25x4+3.25\displaystyle {y}={1.25}{x}^{{4}}+{3.25} and dxdt=0.6\displaystyle {\frac{{{\left.{d}{x}\right.}}}{{{\left.{d}{t}\right.}}}}={0.6}.
Find dydt\displaystyle {\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{t}\right.}}}} when x=2\displaystyle {x}={2}.