Suppose sin3x=32\displaystyle {\sin{{3}}}{x}=-\frac{\sqrt{{{3}}}}{{2}}.

Find all solutions 0x2π\displaystyle {0}\le{x}\le{2}\pi. Give exact values in radians, and type "pi" for π\displaystyle \pi.

x=\displaystyle {x}= (If there is more than one answer, enter the answers separated by commas)