Let B, C and D be fixed points and let A be a moveable point such that line segment AB is parallel to line segment CD. Let a be the distance between C and D and let h be the distance between AB and CD. Find x, the distance between A and B, such that the sum of the areas of Δ\displaystyle \Delta ABE and Δ\displaystyle \Delta CDE is minimized. You may move the slider in the figure below to see the effect of moving point A.

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(a) Let y equal the altitude of Δ\displaystyle \Delta ABE, measured from E to line segment AB. Write the function A(x)\displaystyle {A}{\left({x}\right)} that gives the sum of the areas of Δ\displaystyle \Delta ABE and Δ\displaystyle \Delta CDE. Make sure your function is written in terms of a\displaystyle {a} , h\displaystyle {h} , x\displaystyle {x} , and not y\displaystyle {y} .

      A(x)=\displaystyle {A}{\left({x}\right)}=  

(b) What is the open interval on which A(x)\displaystyle {A}{\left({x}\right)} is defined?

       

(c) A(x)=\displaystyle {A}'{\left({x}\right)}=  

(d) What is the critical number for A(x)\displaystyle {A}{\left({x}\right)} that lies in the interval identified in part (b)? Note: your answer should be expressed in terms of a.

       

(e) Evaluate A(c)\displaystyle {A}{''}{\left({c}\right)} where c is the critical number found in part (d). Note: your answer should be expressed in terms of a and h.

      A(c)=\displaystyle {A}{''}{\left({c}\right)}=  

(f) Since A\displaystyle {A}{''} is for this c value, A(x)\displaystyle {A}{\left({x}\right)} has a by the second derivative test for relative extrema.