Find the integrating factor μ(x)\displaystyle \mu{\left({x}\right)}μ(x) of
y′+7y−cos(x)=0\displaystyle {y}'+{7}{y}-{\cos{{\left({x}\right)}}}={0}y′+7y−cos(x)=0
such that μ(0)=1\displaystyle \mu{\left({0}\right)}={1}μ(0)=1.
μ(x)=\displaystyle \mu{\left({x}\right)}=μ(x)= Preview Question 6
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