Use the geometric series formula 11−y=∑n=0∞yn\displaystyle \frac{{1}}{{{1}-{y}}}={\sum_{{{n}={0}}}^{{\infty}}}{y}^{{n}}1−y1=n=0∑∞yn to express the function as a series:x61+x=∑n=0∞\displaystyle \frac{{x}^{{6}}}{{{1}+{x}}}={\sum_{{{n}={0}}}^{{\infty}}}1+xx6=n=0∑∞ \displaystyle Preview Question 6
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