Use L'Hospital's rule to determine the following limit. Use exact values.
lim
x
→
0
e
3
x
−
1
sin
(
4
x
)
=
\displaystyle \lim_{{{x}\to{0}}}\frac{{{e}^{{{3}{x}}}-{1}}}{{{\sin{{\left({4}{x}\right)}}}}}=
x
→
0
lim
sin
(
4
x
)
e
3
x
−
1
=
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\displaystyle
Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)
Enter DNE for Does Not Exist, oo for Infinity