Use Newton's method to approximate a root of the equation x7+4x4+4=0\displaystyle {x}^{{7}}+{4}{x}^{{4}}+{4}={0} as follows.
Let x0=1\displaystyle {x}_{{0}}={1} be the initial approximation.
The second approximation, x1=\displaystyle {x}_{{1}}=  
and x2=\displaystyle {x}_{{2}}=