A researcher takes sample temperatures in Fahrenheit of 18 days from San Antonio and 16 days from Milwaukee. Use the sample data shown in the table.

Test the claim that the mean temperature in San Antonio is less than the mean temperature in Milwaukee. Use a significance level of $\displaystyle \alpha={0.05}$.
Assume the populations are approximately normally distributed with unequal variances.
Note that list 1 is longer than list 2, so these are 2 independent samples, not matched pairs.

San Antonio	Milwaukee
70.9	64.9
35.1	64.9
70.9	54.7
62.5	53.2
69.7	50.4
27.3	94.6
43	66.7
63.5	73
83.4	68.4
76.1	42.4
55.8	67
79.4	73
43	72.6
63.5	32.8
14.5	79.1
43.7	77
47.8
76.1

The Null Hypotheses is: H₀: μ1 - μ2 = 0

What is the alterative hypothesis? Select the correct symbols for each space. (Note this may view better in full screen mode.)

H_A: μ1 - μ2 ? > < = ≠ Select an answer 1 3.14 0 -1

Based on these hypotheses, find the following. Round answers to 4 decimal places.

Test Statistic =

p-value =

The p-value is Select an answer less than (or equal to) alpha greater than alpha

The correct decision is to Select an answer reject the null hypothesis fail to reject the null hypothesis .

The correct summary would be: Select an answer There is sufficient evidence to support There is not enough evidence to support the claim that the mean temperature in San Antonio is less than the mean temperature in Milwaukee.