Find the power series for f(x)=ln(1−x3)\displaystyle {f{{\left({x}\right)}}}={\ln{{\left({1}-{x}^{{3}}\right)}}}f(x)=ln(1−x3) centered at x=0\displaystyle {x}={0}x=0 by using term-by-term integration or differentiation.
f(x)=∑n=1∞\displaystyle {f{{\left({x}\right)}}}={\sum_{{{n}={1}}}^{{\infty}}}f(x)=n=1∑∞ Preview Question 6
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