[Not graded] Let f(x)=6x\displaystyle {f{{\left({x}\right)}}}=\sqrt{{{6}-{x}}} and g(x)=x2x\displaystyle {g{{\left({x}\right)}}}={x}^{{2}}-{x}.
Then the domain of fg\displaystyle {f}\circ{g} is equal to [a,b]\displaystyle {\left[{a},{b}\right]} for
a=\displaystyle {a}=  
and
b=\displaystyle {b}=