If sin⁡α=−58\displaystyle {\sin{\alpha}}=-\frac{{5}}{{8}} such that α\displaystyle \alpha terminates in quadrant IV and sin⁡β=23\displaystyle {\sin{\beta}}=\frac{{2}}{{3}} such that β\displaystyle \beta terminates in quadrant I then find each of the following exactly. You do not have to rationalize your denominator. 

(a)  sec⁡(α+β)=\displaystyle {\sec{{\left(\alpha+\beta\right)}}}=  

(b)  cot⁡(α−β)=\displaystyle {\cot{{\left(\alpha-\beta\right)}}}=  

(c)  sin⁡(α−β)=\displaystyle {\sin{{\left(\alpha-\beta\right)}}}=  

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