Let

$\displaystyle {B}=$
			1	0	0
			0	0	1
			0	1	0

then find $\displaystyle {B}^{{2}},{B}^{{3}},{B}^{{4}},{B}^{{5}}$ and $\displaystyle {B}^{{6}}$ to figure out the pattern for $\displaystyle {B}^{{n}}$.  
Then find:

 $\displaystyle {B}^{{496}}=$