Find the 6th\displaystyle {6}^{{{t}{h}}}6th term of the geometric sequence:
{243a(−b),81a(−2b),27a(−4b),9a(−8b),…}\displaystyle {\left\lbrace{243}{a}{\left(-{b}\right)},{81}{a}{\left(-{2}{b}\right)},{27}{a}{\left(-{4}{b}\right)},{9}{a}{\left(-{8}{b}\right)},\ldots\right\rbrace}{243a(−b),81a(−2b),27a(−4b),9a(−8b),…}
a6=\displaystyle {a}_{{6}}=a6= Preview Question 6
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