Answer the following True or False.
∫
−
a
a
sin
(
6
x
)
d
x
=
2
∫
0
a
sin
(
6
x
)
d
x
\displaystyle {\int_{{-{a}}}^{{a}}}{\sin{{\left({6}{x}\right)}}}{\left.{d}{x}\right.}={2}{\int_{{0}}^{{a}}}{\sin{{\left({6}{x}\right)}}}{\left.{d}{x}\right.}
∫
−
a
a
sin
(
6
x
)
d
x
=
2
∫
0
a
sin
(
6
x
)
d
x
True
False
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