Answer the following True or False.
Letting u=4−x2\displaystyle {u}={4}-{x}^{{2}}u=4−x2 produces:
∫04−2x4−x2dx=∫4−121udu\displaystyle {\int_{{0}}^{{{4}}}}\frac{{-{2}{x}}}{{{4}-{x}^{{2}}}}{\left.{d}{x}\right.}={\int_{{4}}^{{-{{12}}}}}\frac{{1}}{{u}}{d}{u}∫044−x2−2xdx=∫4−12u1du.
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