Answer the following True or False:

Since the chain and product rules give: $\displaystyle \frac{{d}}{{{\left.{d}{x}\right.}}}\frac{{{f{{\left({x}\right)}}}}}{{{g{{\left({x}\right)}}}}}=\frac{{d}}{{{\left.{d}{x}\right.}}}{f{{\left({x}\right)}}}{\left({g{{\left({x}\right)}}}\right)}^{{-{1}}}={f}'{\left({x}\right)}{\left({g{{\left({x}\right)}}}\right)}^{{-{{1}}}}-{f{{\left({x}\right)}}}{\left({g{{\left({x}\right)}}}\right)}^{{-{2}}}{g}'{\left({x}\right)}$ 

the quotient rule can always be avoided if you remember how to apply the product and chain rules.