Answer the following True or False:
∑n=1∞7((−2)n−1)=71+2=73\displaystyle {\sum_{{{n}={1}}}^{{\infty}}}{7}{\left({\left(-{2}\right)}^{{{n}-{1}}}\right)}=\frac{{7}}{{{1}+{2}}}=\frac{{7}}{{3}}n=1∑∞7((−2)n−1)=1+27=37
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