Use part 2 of the Fundamental Theorem of Calculus to find the derivative of
f
(
x
)
=
∫
−
5
x
t
3
+
5
3
d
t
\displaystyle {f{{\left({x}\right)}}}={\int_{{-{5}}}^{{{x}}}}\sqrt{{{t}^{{3}}+{5}^{{3}}}}{\left.{d}{t}\right.}
f
(
x
)
=
∫
−
5
x
t
3
+
5
3
d
t
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
=
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