Use part 2 of the Fundamental Theorem of Calculus to find the derivative of
F
(
x
)
=
∫
x
3
sin
(
t
4
)
d
t
\displaystyle {F}{\left({x}\right)}={\int_{{{x}}}^{{{3}}}}{\sin{{\left({t}^{{{4}}}\right)}}}{\left.{d}{t}\right.}
F
(
x
)
=
∫
x
3
sin
(
t
4
)
d
t
F
′
(
x
)
\displaystyle {F}'{\left({x}\right)}
F
′
(
x
)
=
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