Find the solution of the following differential equation. Take the constants of integration to be zeros

y′+(2sin⁡(x)cos⁡(x))y=e−sin⁡2(x)\displaystyle {y}'+{\left({2}{\sin{{\left({x}\right)}}}{\cos{{\left({x}\right)}}}\right)}{y}={e}^{{-{{\sin}^{{2}}{\left({x}\right)}}}}

y(x)=\displaystyle {y}{\left({x}\right)}=  

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