Solve the IVP and leave the answer in a form involving a definite integral. Use $\displaystyle {x}$ for both the upper limit of the integral and the variable of integration (this is just for technical issue. But you know that the variable of integration shouldn't be the same as one of the limit of integration).

$\displaystyle {y}'+\frac{{{2}{x}}}{{{1}+{x}^{{2}}}}{y}=\frac{{e}^{{x}}}{{\left({1}+{x}^{{2}}\right)}^{{2}}}$ with $\displaystyle {y}{\left({0}\right)}={1}$