Find the solution to the following differential equation. Take the constants of integration to be zeros

xy+(1+2x2)y=x3ex2\displaystyle {x}{y}'+{\left({1}+{2}{x}^{{2}}\right)}{y}={x}^{{3}}{e}^{{-{x}^{{2}}}}

y(x)=\displaystyle {y}{\left({x}\right)}=