Estimate the slope of the tangent line (rate of change) to f ( x ) = 1 x \displaystyle {f{{\left({x}\right)}}}=\frac{{1}}{{x}} f ( x ) = x 1 at x = 2 \displaystyle {x}={2} x = 2 by finding the slopes of the secant lines through the points listed below.
Then calculate the slope of the tangent line at the given point.
State answers to three decimal places
( 1.8 , 1 1.8 ) \displaystyle {\left({1.8},\frac{{1}}{{1.8}}\right)} ( 1.8 , 1.8 1 ) and ( 2.2 , 1 2.2 ) \displaystyle {\left({2.2},\frac{{1}}{{2.2}}\right)} ( 2.2 , 2.2 1 )
secant slope, m sec = \displaystyle {m}_{{{\sec}}}= m s e c =
( 1.9 , 1 1.9 ) \displaystyle {\left({1.9},\frac{{1}}{{1.9}}\right)} ( 1.9 , 1.9 1 ) and ( 2.1 , 1 2.1 ) \displaystyle {\left({2.1},\frac{{1}}{{2.1}}\right)} ( 2.1 , 2.1 1 )
secant slope, m sec = \displaystyle {m}_{{{\sec}}}= m s e c =
slope of the tangent line, m t = \displaystyle {m}_{{{t}}}= m t =
Submit Try a similar question
[more..]
Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity
Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 Enter DNE for Does Not Exist, oo for Infinity