Use the Remainder Theorem and synthetic division to evaluate the function at the given value.

f(x)=2x5+x4x3+8x27x+9\displaystyle {f{{\left({x}\right)}}}=-{2}{x}^{{5}}+{x}^{{4}}-{x}^{{3}}+{8}{x}^{{2}}-{7}{x}+{9}

f(3)=\displaystyle {f{{\left({3}\right)}}}=