Solve the Initial value problem
y′′+14y′+50y=0,y(0)=2,y′(0)=−17\displaystyle {y}{''}+{14}{y}'+{50}{y}={0},\quad{y}{\left({0}\right)}={2},{y}'{\left({0}\right)}=-{17}y′′+14y′+50y=0,y(0)=2,y′(0)=−17
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