Find the general solution of
y′′+y′+y=xex+e−x(1+2x)\displaystyle {y}{''}+{y}'+{y}={x}{e}^{{x}}+{e}^{{-{x}}}{\left({1}+{2}{x}\right)}y′′+y′+y=xex+e−x(1+2x)
Use lower case c2\displaystyle {c}_{{2}}c2 and c3\displaystyle {c}_{{3}}c3 for the arbitrary constants.
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