Solve the initial value problem
y′′−3y′−10y=7e−2x,y(0)=1,y′(0)=−17\displaystyle {y}{''}-{3}{y}'-{10}{y}={7}{e}^{{-{2}{x}}},{y}{\left({0}\right)}={1},{y}'{\left({0}\right)}=-{17}y′′−3y′−10y=7e−2x,y(0)=1,y′(0)=−17
Submit Try a similar question