Using synthetic division, find one zero of the polynomial
f
(
x
)
=
x
3
+
2
x
2
−
59
x
−
168
\displaystyle {f{{\left({x}\right)}}}={x}^{{3}}+{2}{x}^{{2}}-{59}{x}-{168}
f
(
x
)
=
x
3
+
2
x
2
−
59
x
−
168
then write the polynomial in factored form based on the zero you found:
Zero for this polynomial:
f
(
\displaystyle {f{{(}}}
f
(
)
=
0
\displaystyle {)}={0}
)
=
0
Factors of the polynomial based on the above zero:
f
(
x
)
=
\displaystyle {f{{\left({x}\right)}}}=
f
(
x
)
=
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