A normal distribution has a mean of 48 and a standard deviation of 6. Use the standard normal table to find the indicated probability for a randomly selected x-value from the distribution. Round all probabilities to 5 decimal places.

Find the z score for 43  

P(x43\displaystyle {x}\ge{43}) =

Find the z score for 54  

P(x54\displaystyle {x}\ge{54}) =

P(43x54\displaystyle {43}\le{x}\le{54}) =