Suppose
f
(
x
)
=
4
x
+
3
\displaystyle {f{{\left({x}\right)}}}={4}{x}+{3}
f
(
x
)
=
4
x
+
3
and
g
(
x
)
=
6
x
2
−
x
+
5
\displaystyle {g{{\left({x}\right)}}}={6}{x}^{{2}}-{x}+{5}
g
(
x
)
=
6
x
2
−
x
+
5
.
Then
(
f
g
)
(
x
)
=
\displaystyle {\left({f}{g}\right)}{\left({x}\right)}=
(
f
g
)
(
x
)
=
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