Find the inverse Laplace transform of



F(s)=1sss2+1+eπ2s(3s1s2+1)\displaystyle {F}{\left({s}\right)}=\frac{{1}}{{s}}-\frac{{s}}{{{s}^{{2}}+{1}}}+{e}^{{-\frac{\pi}{{2}}{s}}}{\left(\frac{{{3}{s}-{1}}}{{{s}^{{2}}+{1}}}\right)}

Note: Use u\displaystyle {u} for the step function.
f(t)=\displaystyle {f{{\left({t}\right)}}}=