Find the inverse Laplace transform of
F(s)=1s−ss2+1+e−π2s(3s−1s2+1)\displaystyle {F}{\left({s}\right)}=\frac{{1}}{{s}}-\frac{{s}}{{{s}^{{2}}+{1}}}+{e}^{{-\frac{\pi}{{2}}{s}}}{\left(\frac{{{3}{s}-{1}}}{{{s}^{{2}}+{1}}}\right)}F(s)=s1−s2+1s+e−2πs(s2+13s−1)
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