Simplify exactly:
−2cos(α+3π2)=\displaystyle -{2}{\cos{{\left(\alpha+\frac{{{3}\pi}}{{2}}\right)}}}=−2cos(α+23π)=
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To enter sinα\displaystyle {\sin{\alpha}}sinα or cosα\displaystyle {\cos{\alpha}}cosα in your answer type 'sin(alpha)' or 'cos(alpha)' in the answer box.
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