Simplify exactly:

 10tan(α+2π3)=\displaystyle {10}{\tan{{\left(\alpha+\frac{{{2}\pi}}{{3}}\right)}}}=

 

To enter sinα\displaystyle {\sin{\alpha}} or cosα\displaystyle {\cos{\alpha}} in your answer type 'sin(alpha)' or 'cos(alpha)' in the answer box.