Solve the system by substitution or elimination.
{
5
x
−
4
y
=
1
4
x
−
3
y
=
0
\displaystyle {\left\lbrace\begin{array}{ccccc} {5}{x}&-&{4}{y}&=&{1}\\{4}{x}&-&{3}{y}&=&{0}\end{array}\right.}
{
5
x
4
x
−
−
4
y
3
y
=
=
1
0
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