Simplify the expression y2+4yy216\displaystyle {\frac{{{y}^{{2}}+{4}{y}}}{{{y}^{{2}}-{16}}}}
Give your answer in the form of f(y)g(y).\displaystyle {\frac{{{f{{\left({y}\right)}}}}}{{{g{{\left({y}\right)}}}}}}.

Your answer for the function f(y)\displaystyle {f{{\left({y}\right)}}} is :  
Your answer for the function g(y)\displaystyle {g{{\left({y}\right)}}} is :