Find all solutions on the interval [0,2π)\displaystyle {\left[{0},{2}\pi\right)}. Use exact values. 

 4sin2x2sinx=0\displaystyle {4}{{\sin}^{{2}}{x}}-{2}{\sin{{x}}}={0} 

Separate multiple solutions with a comma. If there are no solutions please enter, "no solution" exactly.