Suppose IQ scores in your community are normally distributed with a mean of 96 and a standard deviation of 15.
The z-score tells you how many units above the average (if Z-score is positive) or below the average (if Z-score is negative) any IQ score is.
Find the IQ score that corresponds to the following z-scores. 

Use the formula $\displaystyle {Z}=\frac{{{X}-\mu}}{\sigma}$ 
  where $\displaystyle \mu$  is the mean, $\displaystyle \sigma$  is the standard deviation, and $\displaystyle {X}$  is the IQ score.

1.  $\displaystyle {Z}=-{0.9},{X}=$ 
   
   
2.  $\displaystyle {Z}={2.26},{X}=$