Let
f
(
x
)
=
(
x
−
10
)
5
−
8
\displaystyle {f{{\left({x}\right)}}}={\left({x}-{10}\right)}^{{5}}-{8}
f
(
x
)
=
(
x
−
10
)
5
−
8
, determine
f
−
1
(
x
)
\displaystyle {{f}^{{-{1}}}{\left({x}\right)}}
f
−
1
(
x
)
.
f
−
1
(
x
)
=
\displaystyle {{f}^{{-{1}}}{\left({x}\right)}}=\
f
−
1
(
x
)
=
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