A line is tangent to the circle (x+4)2+(y+9)2=10\displaystyle {\left({x}+{4}\right)}^{{2}}+{\left({y}+{9}\right)}^{{2}}={10}(x+4)2+(y+9)2=10 at the point (−1,−8)\displaystyle {\left(-{1},-{8}\right)}(−1,−8). Find the equation of the line in slope-intercept form.
y=\displaystyle {y}=y=
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