Let $\displaystyle {f{{\left({x}\right)}}}=\sqrt{{{x}}}$.

Using the definition of derivative at a point, $\displaystyle {f}'{\left({a}\right)}=\lim_{{{x}\rightarrow{a}}}\ {\frac{{{f{{\left({x}\right)}}}-{f{{\left({a}\right)}}}}}{{{x}-{a}}}}$,
enter the expression needed to find the derivative at $\displaystyle {x}={2}$.

$\displaystyle {f}'{\left({2}\right)}=\lim_{{{x}\rightarrow{2}}}\$Preview Question 6 Part 1 of 3  

After evaluating this limit, we see that $\displaystyle {f}'{\left({2}\right)}=$Preview Question 6 Part 2 of 3  

Finally, the equation of the tangent line to $\displaystyle {f{{\left({x}\right)}}}$ where $\displaystyle {x}={2}$ is Preview Question 6 Part 3 of 3