Determine whether x=1\displaystyle {x}={1}x=1 is a solution to the equation.
5(x+2)+4=−7(x−3)\displaystyle {5}{\left({x}+{2}\right)}+{4}=-{7}{\left({x}-{3}\right)}5(x+2)+4=−7(x−3) for x\displaystyle {x}x
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