If
f
(
x
)
=
(
x
2
+
3
x
+
7
)
2
\displaystyle {f{{\left({x}\right)}}}={\left({x}^{{2}}+{3}{x}+{7}\right)}^{{{2}}}
f
(
x
)
=
(
x
2
+
3
x
+
7
)
2
, then
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
=
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