For the standard normal variable Z\displaystyle {Z} , find the probability P(3.86<Z<3.07)\displaystyle {P}{\left(-{3.86}<{Z}<-{3.07}\right)} :

P(3.86<Z<3.07)=\displaystyle {P}{\left(-{3.86}<{Z}<-{3.07}\right)}= (Round the answer to 4 decimal places)