The drug OxyContin (oxycodone) is used to treat pain, but it is dangerous because it is addictive and can be lethal. In clinical trials, 291 subjects were treated with OxyContin and 175 of them developed nausea (based on data from Purdue Pharma L.P.). Use a 1% significance level to test the claim that the proportion of OxyContin users that develop nausea is greater than 60%.

Procedure: Select an answer One mean T Hypothesis Test One proportion Z Hypothesis Test One mean Z Hypothesis Test One variance χ² Hypothesis Test

Assumptions: (select everything that applies)

Step 1. Hypotheses Set-Up:

$\displaystyle {H}_{{0}}:$  Select an answer μ p σ² =	, where Select an answer μ p σ² is the Select an answer population mean population variance population proportion and the units are Select an answer subjects 100%
$\displaystyle {H}_{{a}}:$ Select an answer σ² μ p ? ≠ < >	, and the test is Select an answer Right-Tail Left-Tail Two-Tail

Step 2. The significance level $\displaystyle \alpha=$ %

Step 3. Compute the value of the test statistic: Select an answer z₀ f₀ t₀ χ²₀ = (Round the answer to 3 decimal places)

Step 4. Testing Procedure: (Round the answers to 3 decimal places)

CVA	PVA
Provide the critical value(s) for the Rejection Region:	Compute the P-value of the test statistic:
left CV is and right CV is	P-value is

Step 5. Decision:

CVA	PVA
Is the test statistic in the rejection region?	Is the P-value less than the significance level?
? no yes	? no yes

Conclusion: Select an answer Reject the null hypothesis in favor of the alternative. Do not reject the null hypothesis in favor of the alternative.

Step 6. Interpretation:

At 1% significance level we Select an answer DO DO NOT have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.