A sample of birth weights of 47 girls was taken. Below are the results (in g):
3300.4 | 3962.8 | 2738.6 | 3930.7 | 2633.8 |
3787.2 | 2987.4 | 3543.5 | 3892.9 | 3116.9 |
4039.9 | 3385.2 | 3000.4 | 3068.8 | 3772.2 |
3173.6 | 3105.1 | 2822.3 | 3668.6 | 3762.8 |
2933.3 | 3617.7 | 3534.7 | 2884.9 | 3109.1 |
3435.2 | 3922 | 3390.5 | 2557.7 | 2768.6 |
3541.2 | 4163.4 | 3405.3 | 2844.5 | 3411.3 |
2447.8 | 2420.3 | 2709.4 | 3472.1 | 4303.6 |
2764.5 | 3486.2 | 3696.7 | 3038.4 | 3624 |
2735.9 | 2557.1 |
(Note: The average and the standard deviation of the data are respectively 3286.6 g and 491.42 g.)
Use a 10% significance level to test the claim that the standard deviation of birthweights of girls is different from the standard deviation of birthweights of boys, which is 470 g.
Procedure:
Assumptions: (select everything that applies)
Step 1. Hypotheses Set-Up:
= | , where is the and the units are |
, and the test is |
Step 2. The significance level %
Step 3. Compute the value of the test statistic: = (Round the answer to 3 decimal places)
Step 4. Testing Procedure: (Round the answers to 3 decimal places)
CVA | PVA |
Provide the critical value(s) for the Rejection Region: | Compute the P-value of the test statistic: |
left CV is and right CV is | P-value is |
Step 5. Decision:
CVA | PVA |
Is the test statistic in the rejection region? | Is the P-value less than the significance level? |
Conclusion:
Step 6. Interpretation:
At 10% significance level we have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.
- Question Help:
- Video
- Written Example