A sample of birth weights of 47 girls was taken. Below are the results (in g):

3300.43962.82738.63930.72633.8
3787.22987.43543.53892.93116.9
4039.93385.23000.43068.83772.2
3173.63105.12822.33668.63762.8
2933.33617.73534.72884.93109.1
3435.239223390.52557.72768.6
3541.24163.43405.32844.53411.3
2447.82420.32709.43472.14303.6
2764.53486.23696.73038.43624
2735.92557.1

(Note: The average and the standard deviation of the data are respectively 3286.6 g and 491.42 g.)

Use a 10% significance level to test the claim that the standard deviation of birthweights of girls is different from the standard deviation of birthweights of boys, which is 470 g.

Procedure:

Assumptions: (select everything that applies)

Step 1. Hypotheses Set-Up:

H0:\displaystyle {H}_{{0}}: = , where is the and the units are
 Ha:\displaystyle {H}_{{a}}:  , and the test is

Step 2. The significance level α=\displaystyle \alpha= %

Step 3. Compute the value of the test statistic: = (Round the answer to 3 decimal places)

Step 4. Testing Procedure: (Round the answers to 3 decimal places)

CVA PVA
Provide the critical value(s) for the Rejection Region: Compute the P-value of the test statistic:
left CV is and right CV is P-value is

Step 5. Decision:

CVA PVA
Is the test statistic in the rejection region? Is the P-value less than the significance level?

Conclusion:

Step 6. Interpretation:

At 10% significance level we have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.