The breaking strength of hockey stick shafts made of two different graphite-kevlar composites yields the following results (in Newtons):
Composite 1:
| 455.3 | 436.2 | 462.1 | 472.6 | 432.2 |
| 454.2 | 471.2 | 452.6 | 463.2 | 451 |
| 449.7 | 440.1 |
(Note: The average and the standard deviation of the data are respectively 453.4 Newtons and 12.81 Newtons.)
Composite 2:
| 493.3 | 516 | 458.2 | 528.2 | 456.7 |
| 478.2 | 468.2 | 471.8 | 475.1 | 487.8 |
| 489 | 483.2 | 471.1 | 485.9 |
(Note: The average and the standard deviation of the data are respectively 483.1 Newtons and 19.97 Newtons.)
Use a 10% significance level to test the claim that the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 1 is less than the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 2.
Procedure:
Assumptions: (select everything that applies)
Step 1. Hypotheses Set-Up:
| = | , where the and the units are |
| , and the test is |
Step 2. The significance level %
Step 3. Compute the value of the test statistic: = (Round the answer to 3 decimal places)
Step 4. Testing Procedure: (Round the answers to 3 decimal places)
| CVA | PVA |
| Provide the critical value(s) for the Rejection Region: | Compute the P-value of the test statistic: |
| left CV is and right CV is | P-value is |
Step 5. Decision:
| CVA | PVA |
| Is the test statistic in the rejection region? | Is the P-value less than the significance level? |
Conclusion:
Step 6. Interpretation:
At 10% significance level we have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.
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