The breaking strength of hockey stick shafts made of two different graphite-kevlar composites yields the following results (in Newtons):

Composite 1:

484.1	474.6	490.2	500.3	468.9
499.2	463.4	498.5	478.4	499.1
474.5	480.7	473.8	487.2	479.2

(Note: The average and the standard deviation of the data are respectively 483.5 Newtons and 11.89 Newtons.)

Composite 2:

480	469.1	448.9	505.7	457.1
469.8	456.5	480.6	468.7	451.8
460.2	433.7

(Note: The average and the standard deviation of the data are respectively 465.2 Newtons and 18.46 Newtons.)

Use a 5% significance level to test the claim that the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 1 is less than the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 2.

Procedure: Select an answer Two means Z Hypothesis Test Two paired means Z Hypothesis Test Two variances F Hypothesis Test Two proportions Z Hypothesis Test Two means T (non-pooled) Hypothesis Test Two means T (pooled) Hypothesis Test

Assumptions: (select everything that applies)

Step 1. Hypotheses Set-Up:

$\displaystyle {H}_{{0}}:$ Select an answer μ p₁-p₂ μ₁-μ₂ σ₁²/σ₂² =	, where Select an answer p's are μ's are μ=μ₁-μ₂ is σ's are the Select an answer population proportions difference between population means population means population standard deviations and the units are Select an answer J Watt lbs N
$\displaystyle {H}_{{a}}:$ Select an answer p₁-p₂ σ₁²/σ₂² μ₁-μ₂ μ ? > ≠ <	, and the test is Select an answer Two-Tail Right-Tail Left-Tail

Step 2. The significance level $\displaystyle \alpha=$ %

Step 3. Compute the value of the test statistic: Select an answer t₀ χ²₀ z₀ f₀ = (Round the answer to 3 decimal places)

Step 4. Testing Procedure: (Round the answers to 3 decimal places)

CVA	PVA
Provide the critical value(s) for the Rejection Region:	Compute the P-value of the test statistic:
left CV is and right CV is	P-value is

Step 5. Decision:

CVA	PVA
Is the test statistic in the rejection region?	Is the P-value less than the significance level?
? no yes	? no yes

Conclusion: Select an answer Do not reject the null hypothesis in favor of the alternative. Reject the null hypothesis in favor of the alternative.

Step 6. Interpretation:

At 5% significance level we Select an answer DO DO NOT have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.