The breaking strength of hockey stick shafts made of two different graphite-kevlar composites yields the following results (in Newtons):

Composite 1:

455.3436.2462.1472.6432.2
454.2471.2452.6463.2451
449.7440.1

(Note: The average and the standard deviation of the data are respectively 453.4 Newtons and 12.81 Newtons.)

Composite 2:

493.3516458.2528.2456.7
478.2468.2471.8475.1487.8
489483.2471.1485.9

(Note: The average and the standard deviation of the data are respectively 483.1 Newtons and 19.97 Newtons.)

Use a 10% significance level to test the claim that the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 1 is less than the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 2.

Procedure:

Assumptions: (select everything that applies)

Step 1. Hypotheses Set-Up:

H0:\displaystyle {H}_{{0}}: = , where the and the units are
 Ha:\displaystyle {H}_{{a}}:  , and the test is

Step 2. The significance level α=\displaystyle \alpha= %

Step 3. Compute the value of the test statistic: = (Round the answer to 3 decimal places)

Step 4. Testing Procedure: (Round the answers to 3 decimal places)

CVA PVA
Provide the critical value(s) for the Rejection Region: Compute the P-value of the test statistic:
left CV is and right CV is P-value is

Step 5. Decision:

CVA PVA
Is the test statistic in the rejection region? Is the P-value less than the significance level?

Conclusion:

Step 6. Interpretation:

At 10% significance level we have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.